I don't know where to start here. The Gophers statistical chance of winning the game was significantly diminished by deciding to punt with 6:30 left in the game. The chances of completing ONE 4th and 9 play to keep that drive alive versus needing two quick stops of the Ohio State offense and at least one very quick (likely length of the field) score by your offense. "Betting the farm" on anyone completing a 4th and 9 is a better bet than "betting the farm" on an offense finding a way to score two touchdowns with 2 timeouts and the ball on their own 22 yard line.
That's absurd. It was fourth and nine on their
own 42. The Gophers possessed the ball two more times after that punt. The probabilities are roughly,
Punt:
Probability of Overtime = Probability of a safe punt, hold, TD, hold, TD.
What actually happened = Safe punt, hold, TD, OSU TD, downs.
Go for it:
Probability of Overtime = Probability of ( a first down, TD, hold, TD, hold ) + ( turnover on downs, yield FG, TD, hold, TD, hold, FG )
The probability of #1 is really low because the probablity of a first down is low. The probability of #2 is really, really low because they have to score 17 points instead of 14.
If the ball were on the OSU side of the field it would have been entirely different as the likelihood of an OSU field goal would have been significantly diminished and the risk of going for it would have been at least reasonable.