The gophers don’t control their own destiny

[Some guy]

Here we are in July. If gophers go 9-0 in conference play there are 9 combos where there is a 3 way tie at 9-0


I see 4, 7, and 9 as the only 3 with a greater than 0% chance. And I’m low on Michigan State.

I believe there are 66 combos for the whole conference.

The 9 specific 3-way undefeated combinations involving Minnesota are:

1. Minnesota / Oregon / Rutgers
2. Minnesota / Oregon / Maryland
3. Minnesota / Ohio State / Rutgers
4. Minnesota / Ohio State / Michigan State
5. Minnesota / Nebraska / USC
6. Minnesota / Illinois / Rutgers
7. Minnesota / Illinois / USC
8. Minnesota / Maryland / Michigan State
9. Minnesota / Michigan State / USC

 

[Some guy]

Ohio state, Oregon, Penn state
Oregon, UsC, Penn State
Oregon, Indiana, Penn Staye

 

[IceBoxGopher]

They'll control their destiny if they go 16-0.

 

[gopherbadgerman]

I’d take my chances if they go 9-0

 

[GopherGold01]

We're f'd!

 

[GooningGopher]

I am unsure what the point of this post is other than a probability puzzle.

1) Any team would have a chance of 1/512 of going 9-0 under a coin flip assumption.
2) a random pair avoids playing eachother in a given year of 8/17 ≈ 0.47 a random triple would be (8/17)³ ≈ 0.104
3) All possible triples in B1G would be C(18,3) = 816
4) Actual probabilities of any triple would be roughly 816 × 0.104 × (1/512)³ or about 6.3×10⁻⁷

All that to say, the probabilities of any of the outcomes you proposed are close to zero. At this point in the offseason, the Gophers going 10–2 and making the playoffs is the new manifest destiny.

 

[Jack jones]

Ain’t happening.

 

[The Deliberate Stranger]

If we are in a three way tie at 9-0, I see any scenario not involving Ohio State at zero percent, but also if we have wins at Indiana, Washington and Penn State and home wins vs Iowa and Michigan, I'll put that resume up against anyone in the country

 

[gopherphil]

I am unsure what the point of this post is other than a probability puzzle.

1) Any team would have a chance of 1/512 of going 9-0 under a coin flip assumption.
2) a random pair avoids playing eachother in a given year of 8/17 ≈ 0.47 a random triple would be (8/17)³ ≈ 0.104
3) All possible triples in B1G would be C(18,3) = 816
4) Actual probabilities of any triple would be roughly 816 × 0.104 × (1/512)³ or about 6.3×10⁻⁷

All that to say, the probabilities of any of the outcomes you proposed are close to zero. At this point in the offseason, the Gophers going 10–2 and making the playoffs is the new manifest destiny.

The heat got to the OP.

 

[minnyrules11]

We’ll take the Nebraska going undefeated in conference play out the window.

 

[Some guy]

I am unsure what the point of this post is other than a probability puzzle.

1) Any team would have a chance of 1/512 of going 9-0 under a coin flip assumption.
2) a random pair avoids playing eachother in a given year of 8/17 ≈ 0.47 a random triple would be (8/17)³ ≈ 0.104
3) All possible triples in B1G would be C(18,3) = 816
4) Actual probabilities of any triple would be roughly 816 × 0.104 × (1/512)³ or about 6.3×10⁻⁷

All that to say, the probabilities of any of the outcomes you proposed are close to zero. At this point in the offseason, the Gophers going 10–2 and making the playoffs is the new manifest destiny.

You didn’t have to do all this theoretical math. There is an actual schedule

 

[Some guy]

Ain’t happening.

You don’t say?

 

[bleedsmaroonandgold]

All sarcasm aside, is absurd that there is even an academic possibility that a B1G team could win every B1G game and still not be a B1G champion.

 

[Gophers7NatTitlesBadgers0]

We're f'd!

We can never have nice things.