No, I haven't really 'studied physics'. I just saw the ball land on the end line.
It has been many years, but have studied physics and this conversation got me thinking so I did some calculations on this. The hand written pages are available by request.
I used a stop watch to time how long from foot contact to touchdown 51 yards later on the video you attached. The average I got was 3.02 seconds. Therefore the horizontal velocity (which is a constant assuming no wind help/hurt) was 16.89 yds/sec.
I will assume a launch angle of 40 degrees (I view this as generous considering 45 is optimal for max distance and that kick was not 45 degrees), based on being there and watching it. If the horizontal component of the velocity was 16.89 yds/sec, and it was kicked at a launch angle of 40-degrees from the ground, then the vertical component was 14.17 yds/sec and the vector was 22.05 yds/sec (using sin and cos functions).
With this we can calculate the max height of the ball’s trajectory to be 9.37 yards (28.1 feet) reached 1.51 seconds into flight. Seems reasonable. We can also calculate that it dropped to 10 feet/3.33 yards (goal post height) in an additional 1.06 seconds (2.57 seconds after being kicked).
Going back to our horizontal velocity component of 16.89 yds/sec, we calculate that at the 2.57 second point of its flight it had travelled 43.4 yards (horizontally).
Similar, we can calculate that the ball would have dropped to 5 feet (a nice “catch height” for a returner) after 45.8 yards (2.71 seconds into flight).
The wind is something I couldn’t factor in and would skew this <I>some</I> - as would an angle change, but going with those assumptions above this would correspond to an attempt that was 7.6 yards short and that would have been easily fielded 4.8 yards deep in the end-zone.
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