As I've said before, I don't think that question is worth answering because, if you just look through a schedule and say "Well, I think we're probably better than three of these teams but worse than four and, considering the home/away factor, well, we'll go 3-4," I think you will end up being wrong more often than not.
That's why I gave the example of last season in a prior post. Looking at the schedule and the ratings of our conference opponents, we weren't good enough to beat anyone but we still beat three teams if you include the conference tournament game. There's not as much separating most of these teams as some people think and, on any given night, who knows? I'm pretty confident that we won't beat Purdue or Illinois on the road but there's enough of a chance in the others that on a good night it's possible.
Just applying simple rules of mathematical probability (with a binomial distribution), you can't look at a series of games where you are the underdog (chance is < 50%) and assume you will lose all of them. For example, suppose you play four opponents and you have a 40% chance of beating each. The probability distribution of wins with those four trials is shown in the table below.
WINS | Probability |
0 | 0.1296 |
1 | 0.3456 |
2 | 0.3456 |
3 | 0.1536 |
4 | 0.0256 |
Total | 1 |
As you can see, your chances of winning none of those games is less than 13%. Your chances of winning 1 or 2 is actually about 69%.