BleedGopher
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per The Gazette:
In the unlikely event that Iowa, Wisconsin and Minnesota all have three losses what determines the tie breaker?
Let’s start with how this would look: You’d probably have Iowa lose to Wisconsin (loss No. 3) and beat Minnesota (potential loss No. 2 pending the Penn State result). You have Wisconsin beat Iowa and lose to Minnesota (loss no. 3). But if Minnesota beats Wisconsin and, let’s say it loses to Penn State and Iowa, is Northwestern capable of handing it loss No. 3? It is not. Everyone Hawkeye can vouch for that.
This is the problem with the math. Let’s say Wisconsin beats Minnesota. That could be the Gophers’ third loss, but do you trust Nebraska or Purdue to get the Badgers? No, no one does. So, for sure Iowa has to win this week. Viable opponents for Minnesota and Wisconsin are dwindling.
OK, the math is sketchy. Dean did preface this with “the unlikely event.” Let’s finish the exercise, because you never know.
If three teams are tied, there are eight tiebreakers, with No. 1 being teams compared based on winning percentage in games between the tied teams. So, in the above scenario: Iowa is 1-1, Wisconsin is 1-1 and Minnesota is 1-1.
Next is winning percentage within the division. Iowa would have one loss. The Badgers would have two (say thanks to Illinois). Minnesota would have losses to Iowa and Northwestern. So, Iowa.
You go through the eight tiebreakers. If one team is eliminated in the one through eight, then it’s head-to-head between the two remaining teams.
No. 7 is best overall winning percentage.
No. 8 is, and I quote, “will be chosen by random draw.”
Please, let it come to that. The meltdown would be glorious.
https://www.thegazette.com/subject/...ll-division-tiebreakers-iowa-mailbag-20191107
Go Gophers!!
In the unlikely event that Iowa, Wisconsin and Minnesota all have three losses what determines the tie breaker?
Let’s start with how this would look: You’d probably have Iowa lose to Wisconsin (loss No. 3) and beat Minnesota (potential loss No. 2 pending the Penn State result). You have Wisconsin beat Iowa and lose to Minnesota (loss no. 3). But if Minnesota beats Wisconsin and, let’s say it loses to Penn State and Iowa, is Northwestern capable of handing it loss No. 3? It is not. Everyone Hawkeye can vouch for that.
This is the problem with the math. Let’s say Wisconsin beats Minnesota. That could be the Gophers’ third loss, but do you trust Nebraska or Purdue to get the Badgers? No, no one does. So, for sure Iowa has to win this week. Viable opponents for Minnesota and Wisconsin are dwindling.
OK, the math is sketchy. Dean did preface this with “the unlikely event.” Let’s finish the exercise, because you never know.
If three teams are tied, there are eight tiebreakers, with No. 1 being teams compared based on winning percentage in games between the tied teams. So, in the above scenario: Iowa is 1-1, Wisconsin is 1-1 and Minnesota is 1-1.
Next is winning percentage within the division. Iowa would have one loss. The Badgers would have two (say thanks to Illinois). Minnesota would have losses to Iowa and Northwestern. So, Iowa.
You go through the eight tiebreakers. If one team is eliminated in the one through eight, then it’s head-to-head between the two remaining teams.
No. 7 is best overall winning percentage.
No. 8 is, and I quote, “will be chosen by random draw.”
Please, let it come to that. The meltdown would be glorious.
https://www.thegazette.com/subject/...ll-division-tiebreakers-iowa-mailbag-20191107
Go Gophers!!
